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Aspherical shell with an inner radius $'a'$ and an outer radius $'b' $ is made of conducting material. A point charge $+Q$ is placed at the centre of the spherical shell and a total charge $- q $ is placed on the shell.
Charge $- q $ is distributed on the surfaces as

$- Q$ on the inner surface, $- q$ on outer surface
$- Q$ on the inner surface, $- q + Q$ on the outer surface
$+Q$ on the inner surface, $-q - Q$ on the outer surface
The charge $-q$ is spread uniformly between the inner and outer surface.
Solution

The presence of charge $Q$ at the center of the spherical shell induces a equal and opposite charge on the inner surface of the shell, i.e., $-Q$ at the inner surface. This $-Q$ charge will induce a equal and opposite charge on the outer surface of the shell, i.e., $Q$. Also charge $-q$ is placed on the shell. Therefore total charge on the outer surface is $-q+Q$